The function $y(t)=e^{-2t}cos\ t-e^{-2t}sin\ t\text{,}\ t_0=0$ is a solution of the initial value problem $y''+ay'+by=0$, where $y(t_0)=y_0$ and $y'(t_0)=y_0'$. Determine the constants $a$, $b$, $y_0$, and $y_0'$.
Check out the solution HERE.
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The function $y(t)=e^{-2t}cos\ t-e^{-2t}sin\ t\text{,}\ t_0=0$ is a solution of the initial value problem $y''+ay'+by=0$, where $y(t_0)=y_0$ and $y'(t_0)=y_0'$. Determine the constants $a$, $b$, $y_0$, and $y_0'$.
Check out the solution HERE.